日韩精品一区二区三区高清_久久国产热这里只有精品8_天天做爽夜夜做爽_一本岛在免费一二三区

合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

CS 369代做、代寫Python編程語言

時間:2024-05-24  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



CS 369 2024 Assignment 4
See Canvas for due dates
In the ffrst part of this assignment, we use a Hidden Markov Model to model secondary
structure in protein sequences and implement a couple of algorithms we saw in lectures.
In the second part, we simulate sequences down a tree according to the Jukes-Cantor
model then use distance methods to try to reconstruct the tree.
Write your code in Python and present your code embedded in a report in a Jupyter
Notebook. Make sure you test your code thoroughly and write clear, commented code
that others can understand.
Submit two ffles to Canvas: the .ipynb and .html both showing code and results by 10pm
on the due date.
There are 30 marks in total for this assessment.
1. [14 marks total] Suppose we wish to estimate basic secondary structure in protein
(amino acid) sequences. The model we consider is a simplistic rendition of the
model discussed in S C. Schmidler et al. (2004) Bayesian Segmentation of Protein
Secondary Structure, doi:10.1089/10665270050081496
We assume that at each point of the sequence, the residue is associated with one
of three secondary structures: α-helix, β-strand and loops which we label H, S
and T, respectively. To simplify the problem, we classify the amino acids as either
hydrophobic, hydrophilic or neutral (B, I or N, respectively) so a sequence can be
represented by this 3-letter alphabet.
In a α-helix, the residues are 15% neutral, 20% hydrophobic and 65% hydrophilic.
In a β-strand, they are 30%, 60%, 10% and in a loop they are 70%, 15%, 15%.
Assume that all secondary structures have geometrically distributed length with
α-helices having mean 15 residues, β-strands having a mean of 8 residues and loops
a mean of 6 residues. A β-strand is followed by an α-helix 40% of the time and a
loop 60% of the time. An α-helix is followed by a β-strand 30% of the time and a
loop 70% of the time and a loop is equally likely to be followed by a strand or a
helix. At the start of a sequence, any structure is equally likely.
When writing code below, work in natural logarithms throughout to make your
calculations robust to numerical error.
(a) [3 marks] Sketch a diagram of the HMM (a hand-drawn and scanned picture
is ffne). In your diagram, show only state nodes and transitions. Show the
emission probabilities using a separate table.
Note that the transition probabilities of states to themselves (e.g., aHH) are
not given. Derive them by noticing that you are given the expected lengths
of α-helices, β-strands and loops, and that if a quantity L is geometrically
distributed with parameter p then the expected value of L is E[L] = 1/p.
Make sure you use the correct parametrisation of the geometric distribution
1(noting that you can’t have a secondary structure of length 0) and remember
that
P
l
akl = 1 for any state k.
(b) [3 marks] Write a method to simulate state and symbol sequences of arbitrary
length from the HMM. Your method should take sequence length, and model
parameters (a and e) as arguments. Simulate and print out a state and symbol
sequence of length 200.
(c) [3 mark] Write a method to calculate the natural logarithm of the joint probability
P(x, π). Your method should take x, π, and model parameters as
arguments.
Use your method to calculate P(x, π) for π and x given below and for the
sequences you simulated in Q1b.
π = S,S,H,H,H,T,T,S,S,S,H,T,T,H,H,H,S,S,S,S,S,S
x = B,I,B,B,N,I,N,B,N,I,N,B,I,N,B,I,I,N,B,B,N,N
(d) [5 marks] Implement the forward algorithm for HMMs to calculate the natural
logarithm of the probability P(x). Your method should take x as an argument.
Note that we don’t model the end state here.
Use your method to calculate log(P(x)) for π and x given in Q1c and for the
sequences you simulated in Q1b.
How does P(x) compare to P(x, π) for the examples you calculated? Does
this relationship hold in general? Explain your answer.
22. [16 marks total] In this question you will write a method that simulates random
trees, simulates sequences using a mutation process on these trees, calculate a
distance matrix from the simulated sequences and then, using existing code, reconstruct
 the tree from this distance matrix.
(a) [5 marks] Write a method that simulates trees according to the Yule model
(described below) with takes as input the number of leaves, n, and the branching
 parameter, λ. Use the provided Python classes.
The Yule model is a branching process that suggests a method of constructing
trees with n leaves. From each leaf, start a lineage going back in time. Each
lineage coalesces with others at rate λ. When there k lineages, the total rate
of coalescence in the tree is kλ. Thus, we can generate a Yule tree with n
leaves as follows:
Set k = n,t = 0.
Make n leaf nodes with time t and labeled from 1 to n. This is the set of
available nodes.
While k > 1, iterate:
Generate a time tk ∼ Exp (kλ). Set t = t + tk.
Make a new node, m, with height t and choose two nodes, i and j,
uniformly at random from the set of available nodes. Make i and j
the child nodes of m.
Add m to the set of available nodes and remove i and j from this set.
Set k = k-1.
Simulate 1000 trees with λ = 0.5 and n = 10 and check that the mean height
of the trees (that is, the time of the root node) agrees with the theoretical
mean of 3.86.
Use the provided plot tree method to include a picture of a simulated tree
with 10 leaves and λ = 0.5 in your report. To embed the plot in your report,
include in the ffrst cell of your notebook the command %matplotlib inline
(b) [5 marks] The Jukes-Cantor model of DNA sequence evolution is simple:
each site mutates at rate µ and when a mutation occurs, a new base is chosen
uniformly at random from the four possible bases, {A, C, G, T}. If we ignore
mutations from base X to base X, the mutation rate is
3
4
µ. All sites mutate
independently of each other. A sequence that has evolved over time according
to the Jukes-Cantor model has each base equally likely to occur at each site.
The method mutate is provided to simulate the mutation process.
Write a method to simulate sequences down a simulated tree according to the
Jukes-Cantor model.
Your method should take a tree with n leaves, sequence length L, and a
mutation rate µ. It should return either a matrix of sequences corresponding
to nodes in the tree or the tree with sequences stored at the nodes.
3Your method should generate a uniform random sequence of length L at the
root node and recursively mutate it down the branches of the tree, using the
node heights to calculate branch length.
In your report, include a simulated tree with n = 10 and λ = 0.5 and a set
of sequences of length L = 20 and mutation parameter µ = 0.5 simulated on
that tree.
(c) [3 marks] Write a method to calculate the Jukes-Cantor distance matrix, d,
from a set of sequences, where dij is the distance between the ith and the
jth sequences. Recall that the Jukes-Cantor distance for sequences x and y
is deffned by
where fxy is the fraction of differing sites between x and y. Since we will be
dealing with short sequences, use the following deffnition of fxy so that the
distances are well-deffned:
fxy = min
where Dxy is the number of differing sites between x and y and L is the length
of x.
Include a simulated set of sequences of length L = 20 from the tree leaves and
corresponding distance matrix in your report for a tree with n = 10, λ = 0.5
and mutation parameter µ = 0.5.
(d) [3 marks] Now simulate a tree with n = 10 and λ = 0.5 and on that tree,
simulate three sets of sequences with lengths L = 20, L = 50 and L = 200,
respectively, with ffxed µ = 0.1. For each simulated set of sequences, calculate
the distance matrix and print it out.
Then reconstruct the tree using the provided compute upgma tree method.
Use the plot tree method to include a plot of the original tree and a plot of
the reconstructed tree for each distance matrix.
Comment on the quality of the reconstructions and the effect that increasing
the sequence length has on the accuracy of the reconstruction.

請加QQ:99515681  郵箱:99515681@qq.com   WX:codinghelp










 

掃一掃在手機打開當前頁
  • 上一篇:代寫CS373 COIN、代做Python設計程序
  • 下一篇:CSSE7030代做、代寫Python程序設計
  • 無相關信息
    合肥生活資訊

    合肥圖文信息
    有限元分析 CAE仿真分析服務-企業/產品研發/客戶要求/設計優化
    有限元分析 CAE仿真分析服務-企業/產品研發
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    出評 開團工具
    出評 開團工具
    挖掘機濾芯提升發動機性能
    挖掘機濾芯提升發動機性能
    海信羅馬假日洗衣機亮相AWE  復古美學與現代科技完美結合
    海信羅馬假日洗衣機亮相AWE 復古美學與現代
    合肥機場巴士4號線
    合肥機場巴士4號線
    合肥機場巴士3號線
    合肥機場巴士3號線
    合肥機場巴士2號線
    合肥機場巴士2號線
  • 短信驗證碼 豆包 幣安下載 目錄網

    關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
    ICP備06013414號-3 公安備 42010502001045

    日韩精品一区二区三区高清_久久国产热这里只有精品8_天天做爽夜夜做爽_一本岛在免费一二三区

      <em id="rw4ev"></em>

        <tr id="rw4ev"></tr>

        <nav id="rw4ev"></nav>
        <strike id="rw4ev"><pre id="rw4ev"></pre></strike>
        亚洲视频电影图片偷拍一区| 国产日韩av一区二区| 国产欧美精品一区aⅴ影院| 国产精品最新自拍| 欧美精品在线一区二区| 欧美激情视频一区二区三区在线播放| 国产专区一区| 激情婷婷亚洲| 欧美啪啪一区| 亚洲韩国一区二区三区| 伊人色综合久久天天| 欧美精品久久久久久久久老牛影院| 欧美网站大全在线观看| 欧美激情欧美狂野欧美精品| 日韩午夜电影在线观看| 欧美日韩人人澡狠狠躁视频| 欧美久久久久中文字幕| 国产精品久久亚洲7777| 亚洲一级高清| 亚洲免费在线看| 国产亚洲综合精品| 国产一区二区在线免费观看| 日韩视频精品在线| 国产日本欧美在线观看| 欧美日韩在线视频观看| 欧美精品网站| 一区二区三区国产在线| 欧美日韩精品一二三区| 精品动漫3d一区二区三区| 久久疯狂做爰流白浆xx| 亚洲欧洲综合另类| 激情五月婷婷综合| 欧美三级网页| 在线精品视频一区二区| 欧美日本二区| 亚洲第一免费播放区| 欧美三级视频在线观看| 国产亚洲一区在线| 国产精品videosex极品| 欧美成人午夜77777| 欧美护士18xxxxhd| 久久在线免费观看视频| 老司机午夜精品| 亚洲一区制服诱惑| 亚洲精品久久嫩草网站秘色| 久久久久久自在自线| 国产日韩亚洲欧美综合| 亚洲高清一区二区三区| 在线观看日韩专区| 久久综合99re88久久爱| 欧美一区二区三区男人的天堂| 欧美激情女人20p| 亚洲福利视频在线| 欧美一激情一区二区三区| 国模私拍一区二区三区| 欧美国产一区视频在线观看| 欧美人与禽猛交乱配| 久久偷窥视频| 欧美成人中文字幕在线| 欧美激情中文不卡| 影音先锋欧美精品| 久久精品夜夜夜夜久久| 国产区精品视频| 亚洲国产欧美一区| 欧美日韩国产一区精品一区| 日韩天天综合| 亚洲综合色在线| 亚洲午夜精品久久久久久app| 欧美一级二级三级蜜桃| 国产美女高潮久久白浆| 99精品99久久久久久宅男| 久久裸体艺术| 在线观看视频一区二区| 久久www免费人成看片高清| 国产亚洲综合在线| 亚洲一区二区三区四区五区黄| 日韩视频永久免费| 亚洲女人天堂av| 欧美日韩精品一区二区天天拍小说| 亚洲美女免费精品视频在线观看| 久久成人人人人精品欧| 国产精品久久久久久五月尺| 国产美女精品视频| 精品成人在线观看| 欧美日韩第一区日日骚| 伊人男人综合视频网| 欧美视频在线一区| 亚洲国产成人精品视频| 欧美精品色网| 亚洲一级黄色av| 在线一区二区视频| 99热免费精品| 亚洲影院污污.| 国产欧美欧洲在线观看| 欧美日韩综合久久| 欧美在线视频一区| 国产亚洲欧美一区| 亚洲午夜未删减在线观看| 尤物yw午夜国产精品视频明星| 久久国产一区二区| 国产精品国色综合久久| 欧美日韩综合在线| 欧美国产日韩一区二区三区| 久久嫩草精品久久久久| 欧美成人亚洲| 免费在线观看一区二区| 国内精品久久久久久| 国产精品国产三级国产普通话99| 亚洲国产精品一区| 国产无遮挡一区二区三区毛片日本| 国产日本亚洲高清| 国产视频一区二区在线观看| 国产午夜精品一区二区三区视频| 一本不卡影院| 亚洲另类在线一区| 国产麻豆精品theporn| 国产欧美在线| 一区二区三区四区国产精品| 国产精品美女久久久久av超清| 亚洲乱码视频| 国产精品网站在线观看| 欧美精品国产一区二区| 亚洲视频一区二区在线观看| 亚洲国产成人久久| 亚洲精品欧美专区| 国模精品娜娜一二三区| 黄色一区二区三区| 欧美国产精品中文字幕| 老司机免费视频久久| 国产精品午夜电影| 亚洲一区二区三区激情| 一区二区三区久久久| 欧美在线免费观看视频| 美女性感视频久久久| 欧美日韩不卡合集视频| 在线观看中文字幕亚洲| 国产精品日日摸夜夜摸av| 亚洲免费在线看| 亚洲欧美日韩人成在线播放| 99v久久综合狠狠综合久久| 国产亚洲日本欧美韩国| 久久久久88色偷偷免费| 亚洲欧美国产日韩中文字幕| 国产日本欧洲亚洲| 久久久久久久高潮| 欧美日韩一视频区二区| 欧美成人综合网站| 欧美刺激性大交免费视频| 嫩草伊人久久精品少妇av杨幂| 亚洲高清免费视频| 国产一级精品aaaaa看| 欧美制服第一页| 国产精品尤物福利片在线观看| 9色国产精品| 国产精品影音先锋| 国产精品豆花视频| 欧美人与性动交a欧美精品| 精品电影一区| 欧美日韩极品在线观看一区| 亚洲毛片在线观看| 激情校园亚洲| 欧美刺激午夜性久久久久久久| 欧美国产日韩在线| 国产欧美日韩精品a在线观看|