日韩精品一区二区三区高清_久久国产热这里只有精品8_天天做爽夜夜做爽_一本岛在免费一二三区

合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

代寫SI 100B、代做Python設計程序
代寫SI 100B、代做Python設計程序

時間:2024-11-01  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



SI 100B Programming Assignment 2
SI 100B TA Team
October 23, 2024
1
Notice
• This homework is due 10:00 AM October 30, Wednesday, please start early.
• The problems should be solved individually. You should submit solutions for all problems to the online
judge (OJ) system, which will give a score for each submission automatically.
• You may discuss course material, programming languages, general techniques, and share test cases with
others.
• You’re encouraged to ask any question about problem description, environment setup, error informa tion, grammar, functions, methods etc., or post general ideas at Piazza. It can help others too!
• However, you may NOT read, possess, copy, or submit any part of other’s solution. You may not ask
others to directly debug your program or provide specific lines of solution. You should not access an other person’s account. Also, do not offer such help, and protect your account and code. Giving or
receiving inappropriate help is plagiarism, an infringement of academic integrity.
• You are not allowed to write your solution directly by or based on code generated by AI tools.
• Good luck and have fun!
2
1 UNFORTUNATE STOCKHOLDER
1 Unfortunate Stockholder
“I really hate green,” the poor man sighed, looking down, and found his beloved Alexandra Nikolaevna
Petrovskaya lying on the floor, stiff and cold. With her gone, his nearly hairless head now has one less hair.
A month ago, he was still a rich man, with positive daily profit from his investments. However, without
him noticing, some of his stocks had been falling for several days, and then suddenly hit the lower limit.
Quicker than he could take any actions, his other stocks also began falling.
Because he had so many stocks, he only checked the total profit every day.“Oh God! How I wish I had a
tool that can tell me the details of my stocks!”
1.1 Task
As it happens, you know how to use python, and you will kindly fulfill his wish by writing a python
program to give the details of his stocks. You will be given a list of numbers, representing the profit of his
stocks, and a series of queries. For each query, you should perform the corresponding operation and print the
result.
1.2 Input/Output Specification
1.2.1 Input
The first line contains a string of float numbers, representing the profit of the stocks.
The second line contains a single positive integer n, indicating the number of queries.
Each of the following n lines contains a query, with details shown in the Table below. All queries will be
given in one of the formats
• query, operation
• query, operation, start_index, end_index, step
query, operation, start_index, end_index, step means querying on the profit of a subset of the stocks ob tained by performing slicing operation. It is guaranteed that start_index, end_index and step are all integers.
If the subset of the stocks to be queried is empty, print Querying on empty list! (with a single space
at the end of the output) and do nothing else.
1.2.2 Output
n lines, each line the result of the query.
3
1.2 Input/Output Specification 1 UNFORTUNATE STOCKHOLDER
Query Operation Example Input Result
find
min find, min the min profit amongst all stocks
find, min, 1, 3, 1 the min profit amongst the sliced subset of stocks
max
find, max the max profit amongst all stocks
find, max, 5, 9, 2 the max profit amongst the sliced subset of stocks
index
a single index, 10 the profit of the stock with index i
positive integer i
slice index, slice, 2, 3, 1 the list of profits of the sliced subset of stocks
compute
avg
compute, avg the average profit of all stocks
compute, avg, 5, 12, 3 the average profit of the sliced subset of stocks
all compute, all the total profit of all stocks
compute, all, 6, 3, 2 the total profit of the sliced subset of stocks
reorder
asc
reorder, asc the reordered list of profits
of all stocks in ascending order
reorder, asc, 7, 30, 1 the list of profits with the profits of the
sliced stocks reordered in ascending order
desc
reorder, desc the reordered list of profits
of all stocks in descending order
reorder, desc, 3, 4, 2 the list of profits with the profits of the
sliced stocks reordered in descending order
rev
reorder, rev the reordered list of profits
of all stocks in reverse order
reorder, rev, 9, 3, 3 the list of profits with the profits of the
sliced stocks reordered in reverse order
1.2.3 Example
1. Input
1 4 5 3 4 2 5 −2 −3 0 2
5
find, min
find, max, 0, 3, 1
compute, avg, 2, 12, 1
reorder, rev
reorder, asc, 1, 6, 1
Output
−3.0
5.0
1.7777777777777777
[2.0, 0.0, −3.0, −2.0, 5.0, 2.0, 4.0, 3.0, 5.0, 4.0, 1.0]
[2.0, −3.0, −2.0, 0.0, 2.0, 5.0, 4.0, 3.0, 5.0, 4.0, 1.0]
4
1.3 Hint 2 AVERAGE RUNNING SPEED
2. Input
1 2 3 4 5 6
5
index, 5
index, slice, 1, 4, 2
compute, all
reorder, desc, 6, 3, −1
find, max, 2, 4, 1
Output
6.0
[2.0, 4.0]
21.0
[1.0, 2.0, 3.0, 4.0, 5.0, 6.0]
4.0
1.3 Hint
After each reorder query, the list is reordered (i.e., it is mutated), as shown in the examples.
2 Average Running Speed
As part of promoting a healthy lifestyle, the university has introduced a running App. The App generates
data points consecutively containing the student’s positions and timestamps during their running sessions.
The App helps generate useful statistics, such as distance covered and average speed. And students can freely
select specific data points for customized analysis.
2.1 Task
You are tasked with writing a program to process data points of a running session and then evaluate
a runner’s performance. Your program receives n data points at the beginning. The i-th data point Pi =
(xi
, yi
, ti), where xi and yi are the runner’s 2D coordinates, ti
is the timestamp measured in seconds. For
simplicity, we assume that runners travels along a straight path between two adjacent points, so the distance
between two adjacent data points is estimated using the Euclidean distance formula:
D(Pk, Pk−1) = √
(xk−xk−1)
2 + (yk−yk−1)
2
5
2.2 Input/Output Specification 2 AVERAGE RUNNING SPEED
Firstly, you need to estimate the average speed V of the entire session, note that the session starts at P0 and
ends at Pn−1:
V =
∑n
k=1 D(Pk, Pk−1)
tn−1 − t0
Then the runner will freely select m subsections, with the i-th subsection represented by the indices of two
data points, starti and endi
. And the runner wants to know what the average running speed is for each
subsection, i.e., the average speed V i running through Pstarti
, Pstarti+1, . . . , Pendi−1, Pendi
2.2 Input/Output Specification
2.2.1 Input
The first line contains a single integer n, the number of data points in the running session (2 ≤ n ≤ 100).
The next n lines of data points contains three integers each: xi
, yi
, ti
, where xi and yi
is the runner’s
coordinate (−100 ≤ xi
, yi ≤ 100), ti
is the timestamp at the i-th data point (0 ≤ t0 < t1 < t2 . . . < tn−1 ≤
103
).
The next line contains a single integer m, the number of the selected subsections.
The next m lines contains two values each: starti
, endi
, which represents the indices of start point and
end point of the i-th subsection (0 ≤ starti < endi < n).
2.2.2 Output
The first line is the average speed V of the entire session. And the next m lines: each line contains the
average speed V i for the i-th subsection. V and V i should be formatted to three decimal places.
2.2.3 Example
1. Input
4
1 2 1
** 5
4 8 12
2 1 18
1
1 3
Output
1.129
1.009
6
3 I OR E
2. Input
5
48 8 2
−83 −85 4
60 14 11
−37 −37 19
−15 −31 20
2
3 4
0 2
Output
25.943
22.804
37.176
3 I or E
Myers–Briggs Type Indicator (MBTI) is a assessment particularly popular in social occasions. There is
one dimension: energy orientation, which is divided into introversion and extraversion—— extraverted person
obtains energy from social interactions, while introverted person obtains energy from self-reflection.
However, a person’s energy orientation is not fixed. For example, a person who is initially classified as
introverted may turn out to be extraverted under some circumstances.
3.1 Task
In this scenario, a meeting consists of participants of three initial orientations: “E”, “I”, and “i”. You are
given a seating arrangement represented as an n × m matrix where n is the number of rows. And each seat
position indicates the energy orientation of a participant (E, I, or i). Your task is to print out the final energy
orientation in matrix format.
Participants will sit one by one, from the first row to the last row, and within each row, from left to right.
During this process, if an “i” participant is surrounded by introverted person (either “I” or “i”), they will change
their orientation to extraverted, denoted as “e”. A participant is considered surrounded by introverted person
if all their adjacent neighbors (up, down, left, right) are either I or i. If the participant is on the boundary
or corner, only the existing neighbors are considered.
There is a special case when the last participant seated: first update the previously seated participants
before considering the last one, in order to avoid potential conflicts.
7
3.2 Input/Output Specification 3 I OR E
3.2 Input/Output Specification
3.2.1 Input
The first line contains two integers n and m, representing the dimensions of the seating matrix (n × m),
(2 ≤ n, m ≤ 50). The following n lines each contain m separated characters c ∈ {E, I, i}, indicating the
energy orientation of the participants in each seat.
3.2.2 Output
You should output n lines, each containing one list, representing the final energy orientation of the par ticipants after they are seated in order.
3.2.3 Example
1. Input
3 4
E I i I
i I i i
i I I i
Output
['E', 'I', 'e', 'I']
['i', 'I', 'i', 'e']
['e', 'I', 'I', 'i']
Case Explanation: for convenience, we use a tuple (i, j) (count from 1), to represent the seat located
at the i-th row and j-th column. The orientation of the participant changed in the following order:
(a) (1, 3) changed when (2, 3) seated.
(b) (3, 1) changed when (3, 2) seated.
(c) (2, 3) changed when (3, 3) seated. Remember to update the previously seated participants before
the last one.
2. Input
5 5
E I i I E
i I i I I
I i I i E
I I i i I
i I I I i
8
4 TURTLE BLIND BOXES
Output
['E', 'I', 'e', 'I', 'E']
['i', 'I', 'i', 'I', 'I']
['I', 'e', 'I', 'i', 'E']
['I', 'I', 'e', 'i', 'I']
['e', 'I', 'I', 'I', 'e']
Case Explanation: The orientation of the participant changed in the following order:
(a) (1, 3) changed when (2, 3) seated.
(b) (3, 2) changed when (4, 2) seated.
(c) (5, 1) changed when (5, 2) seated.
(d) (4, 3) changed when (5, 3) seated.
(e) (5, 5) changed when (5, 5) seated.
4 Turtle Blind Boxes
Blind box opening games have become increasingly popular on platforms such as TikTok. In this assign ment, you will simulate a blind box opening game where the contents are small glass turtles of different colors
and patterns. The objective is to simulate the entire process of purchasing, opening, and placing these turtles
in a grid, following specific rules to either eliminate or reward the player with additional blind boxes based
on turtle combinations.
Each turtle has a color and a pattern, with the following possibilities:
• Colors: Red, Orange, Yellow, Green, Blue
• Patterns: Patterned, Unpatterned
The game uses a 3x3 grid to display the turtles, and there are several conditions that trigger rewards or elimi nations during the gameplay.
4.1 Task
You are required to write a Python program that simulates this turtle blind box game. The game follows
specific rules for rewarding the player with extra blind boxes or eliminating turtles from the grid. The detailed
task breakdown is as follows:
1. Get Blind Box Content: Each blind box contains one glass turtle with a randomly generated color and
pattern combination.
9
4.2 Input/Output Specification 4 TURTLE BLIND BOXES
2. Wish Mechanism: The player can wish for a specific color and pattern combination. If a turtle match ing the player’s wish is opened, they are immediately rewarded with one additional blind box.
3. Grid Filling: Each turtle is placed in a 3x3 grid (like a Tic-Tac-Toe board), and the turtles are placed
in the grid according to the numbered order of the cells (1 to 9), where 1 is the top-left and 9 is the
bottom-right.
4. Elimination and Reward Rules: After the grid is filled or all blind boxes have been opened, perform
the following operations in the specified order:
(a) All Different: If the grid is full and all turtles in the grid are different, remove all turtles and
reward the player with 5 additional blind boxes.
(b) Three of a Kind: If three identical turtles align horizontally, vertically, or diagonally, reward the
player with 5 additional blind boxes. The turtles remain in the grid. If there are multiple triples at
the same time, each triple should be given 5 new blind boxes.
(c) Pairs: If two identical turtles are found, they are eliminated from the grid, and the player is
rewarded with 1 additional blind box per pair. Turtles in cells with smaller numbers (lower numbered positions in the grid) are prioritized for removal.
5. End Condition: The game ends when no more blind boxes are available, and no turtles can be elimi nated.
4.2 Input/Output Specification
4.2.1 Input
The program will accept the following four lines of input:
1. The number of initial blind boxes purchased.
2. The player’s wish for a specific turtle’s color and pattern. Use two letters separated by a space to repre sent turtle.
3. A list of randomly generated turtles, with two lines:
• The first line represents the colors of the turtles, using the first letter of each color: R (Red), O
(Orange), Y (Yellow), G (Green), B (Blue).
• The second line represents the patterns of the turtles, using the first letter of each pattern: P
(Patterned), U (Unpatterned).
10
4.2 Input/Output Specification 4 TURTLE BLIND BOXES
The color and pattern of the i-th turtle are represented by the i-th letter in the third and fourth rows. The
number of turtles provided is undetermined, but it’s guaranteed to be larger than the number required for the
simulation.
4.2.2 Output
At the end of the game, output the list of eliminated turtles in the order they were removed from the grid.
Turtles should be represented by tuples of (color, pattern). At the end of the game, the remaining turtles in the
grid should also be eliminated in the order of the numbers in the nine-square grid. You can use print(list)
directly.
4.2.3 Example
1. Input
10
R U
YOBOOBRGOGYBYRYYGBO
UUUUPUUPPPUUUUPUUPU
Output
[('O', 'U'), ('O', 'U'), ('B', 'U'), ('B', 'U'), ('O', 'P'), ('O', 'P'),
('Y', 'U'), ('Y', 'U'), ('G', 'P'), ('G', 'P'), ('R', 'U'), ('R', 'U'),
('Y', 'U'), ('Y', 'U'), ('O', 'U'), ('G', 'U'), ('B', 'P'), ('B', 'U'),
('Y', 'P')]
2. Input
12
R P
RYOYYYROBYRBGGYOGBBYOBYBRYGOROROYGORGOY
PUPPPPUUPPPUUUPPPUPUPPUUPUPUPPUUUUPUUPU
Output
[('Y', 'P'), ('Y', 'P'), ('R', 'P'), ('R', 'P'), ('Y', 'P'), ('Y', 'P'),
('G', 'U'), ('G', 'U'), ('O', 'P'), ('O', 'P'), ('B', 'U'), ('B', 'U'),
('B', 'P'), ('B', 'P'), ('Y', 'U'), ('Y', 'U'), ('B', 'U'), ('R', 'P'),
('O', 'P'), ('B', 'P'), ('G', 'P'), ('Y', 'P'), ('R', 'U'), ('O', 'U'),
('Y', 'U'), ('Y', 'U'), ('Y', 'U'), ('O', 'U'), ('O', 'U'), ('O', 'P'),
('O', 'P'), ('R', 'U'), ('R', 'U'), ('G', 'U'), ('G', 'U'), ('Y', 'U'),
('G', 'P'), ('O', 'P'), ('R', 'P')]
11
4.3 Hint 4 TURTLE BLIND BOXES
4.3 Hint
• Randomly generate test data for debugging: To test your implementation, you can generate random
turtle combinations and simulate different scenarios (e.g., many identical turtles, all different turtles) to
check if the elimination rules are applied correctly.
• Pay attention to the execution order: Make sure that the elimination rules (e.g., three of a kind,
pairs, all different) are applied in the correct sequence. Follow the order of operations as specified in
the task to ensure accurate simulation.
• Modular design: During the implementation process, keep your code modular by breaking down dif ferent functionalities (e.g., adding turtles to the grid, checking for three of a kind, eliminating pairs) into
separate functions. This will make your code easier to understand, debug, and extend.
12

請加QQ:99515681  郵箱:99515681@qq.com   WX:codinghelp




 

掃一掃在手機打開當前頁
  • 上一篇:CSCI 201代做、代寫c/c++,Python編程
  • 下一篇:CE243編程代寫、代做C/C++程序語言
  • 無相關信息
    合肥生活資訊

    合肥圖文信息
    釘釘簽到打卡位置修改神器,2026怎么修改定位在范圍內
    釘釘簽到打卡位置修改神器,2026怎么修改定
    2025年10月份更新拼多多改銷助手小象助手多多出評軟件
    2025年10月份更新拼多多改銷助手小象助手多
    有限元分析 CAE仿真分析服務-企業/產品研發/客戶要求/設計優化
    有限元分析 CAE仿真分析服務-企業/產品研發
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    出評 開團工具
    出評 開團工具
    挖掘機濾芯提升發動機性能
    挖掘機濾芯提升發動機性能
    海信羅馬假日洗衣機亮相AWE  復古美學與現代科技完美結合
    海信羅馬假日洗衣機亮相AWE 復古美學與現代
    合肥機場巴士4號線
    合肥機場巴士4號線
  • 短信驗證碼 豆包網頁版入口 目錄網 排行網

    關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
    ICP備06013414號-3 公安備 42010502001045

    日韩精品一区二区三区高清_久久国产热这里只有精品8_天天做爽夜夜做爽_一本岛在免费一二三区

      <em id="rw4ev"></em>

        <tr id="rw4ev"></tr>

        <nav id="rw4ev"></nav>
        <strike id="rw4ev"><pre id="rw4ev"></pre></strike>
        亚洲高清在线观看一区| 欧美高清在线视频观看不卡| 久久精品久久99精品久久| 国产一区二区电影在线观看| 久久成人国产精品| 国产精品欧美日韩一区| 欧美高清自拍一区| av成人免费观看| 国产精品国码视频| 欧美精品一区二区精品网| 久久九九精品| 久久精品夜夜夜夜久久| 一区在线视频观看| 国产精品久久九九| 亚洲成人在线网| 久久婷婷蜜乳一本欲蜜臀| 欧美国产激情| 亚洲精品久久久久中文字幕欢迎你| 亚洲国产精品久久久久婷婷老年| 国产日产欧产精品推荐色| 久久蜜桃av一区精品变态类天堂| 欧美猛交免费看| 欧美一区二区国产| 欧美日韩喷水| 欧美极品aⅴ影院| 欧美日韩国产一区二区三区| 玖玖综合伊人| 国模 一区 二区 三区| 国产精品视频网站| 亚洲欧美日韩第一区| 国产视频一区免费看| 亚洲精品视频免费在线观看| 免费不卡亚洲欧美| 国产一区在线视频| 欧美精品手机在线| 日韩视频一区二区三区在线播放| 久久久久九九九九| 国产精品一区二区在线观看网站| 欧美成人午夜77777| 欧美日韩黄色一区二区| 午夜激情一区| 欧美日韩国产高清视频| 亚洲一区999| 亚洲毛片在线| 亚洲在线观看免费视频| 欧美精品观看| 欧美午夜精品电影| 久久综合五月天婷婷伊人| 久久香蕉精品| 午夜精品99久久免费| 久久久久久久久久码影片| 亚洲精品综合精品自拍| 欧美日韩一区在线观看| 国产日韩精品久久| 日韩视频一区二区三区在线播放| 欧美成人午夜激情视频| 国产美女精品一区二区三区| 欧美色欧美亚洲另类七区| 麻豆91精品| 久久国产精品久久久久久电车| 久久在线91| 亚洲美洲欧洲综合国产一区| 亚洲精品一区在线| 欧美视频一区二区三区| 亚洲激精日韩激精欧美精品| 国产精品久久综合| 一区二区冒白浆视频| 国产精品久久久久久久电影| 欧美极品欧美精品欧美视频| 国产精品久久久久久久久借妻| 亚洲深夜影院| 亚洲人成亚洲人成在线观看| 亚洲影视九九影院在线观看| 免费亚洲婷婷| 欧美三级中文字幕在线观看| 一区二区三区欧美视频| 久久综合网色—综合色88| 亚洲一区美女视频在线观看免费| 亚洲欧美日韩国产中文在线| 久久国产精品亚洲77777| 亚洲最新在线视频| 亚洲精品综合在线| 亚洲成色999久久网站| 欧美淫片网站| 欧美日韩国产在线一区| 久久精品国产久精国产一老狼| 久久久人成影片一区二区三区观看| 国产日韩欧美综合一区| 国产在线拍偷自揄拍精品| 欧美主播一区二区三区美女 久久精品人| 一区二区电影免费在线观看| 一区二区三区色| 久久久久久日产精品| 欧美成人免费播放| 亚洲精品永久免费| 久久亚洲精品一区| 欧美国产高清| 欧美国产精品va在线观看| 一区在线视频| 欧美性色aⅴ视频一区日韩精品| 蜜桃av一区| 麻豆精品一区二区av白丝在线| 在线一区二区三区四区五区| 免费观看一级特黄欧美大片| 亚洲视频免费看| 国产精品毛片高清在线完整版| 欧美日韩视频不卡| 国产精品久久二区二区| 伊人狠狠色丁香综合尤物| 欧美日韩一级视频| 亚洲国产高清在线观看视频| 欧美在线免费观看| 欧美成年人视频网站| 久久久久久久999| 女女同性女同一区二区三区91| 蜜臀99久久精品久久久久久软件| 国产一区二区成人久久免费影院| 国产精品久久久久av| 这里只有精品视频| 欧美激情精品久久久久久蜜臀| 亚洲精美视频| 亚洲免费电影在线| 免费在线观看精品| 亚洲国产婷婷综合在线精品| 美女黄网久久| 日韩午夜剧场| 国产精品天天看| 精品粉嫩aⅴ一区二区三区四区| 欧美成人午夜影院| 亚洲欧美资源在线| 香蕉成人啪国产精品视频综合网| 国产精品一区二区三区四区五区| 99精品热视频只有精品10| 欧美精品亚洲精品| 亚洲一区高清| 亚洲女人天堂成人av在线| 国产一区日韩一区| 韩国一区二区三区美女美女秀| 亚洲国产精品成人综合| 欧美日本一区二区视频在线观看| 亚洲一区二区精品在线| 欧美jizz19hd性欧美| 亚洲一区二区成人| 欧美日韩免费在线| 国产在线观看91精品一区| 国产精品国产a级| 精品不卡一区二区三区| 久久久久九九九| 亚洲一区二区三区精品在线观看| 欧美了一区在线观看| 亚洲国产裸拍裸体视频在线观看乱了| 亚洲欧美综合v| 欧美先锋影音| 欧美精品v日韩精品v国产精品| 久久不射网站| 久久精品视频在线看| 国产精品分类| 国产精品国产三级国产普通话蜜臀| 亚洲久色影视| 午夜亚洲一区| 亚洲一区二区三区免费观看| 最新国产成人在线观看| 欧美激情视频免费观看| 欧美不卡高清|