日韩精品一区二区三区高清_久久国产热这里只有精品8_天天做爽夜夜做爽_一本岛在免费一二三区

合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

代寫SI 100B、代做Python設計程序
代寫SI 100B、代做Python設計程序

時間:2024-11-01  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



SI 100B Programming Assignment 2
SI 100B TA Team
October 23, 2024
1
Notice
• This homework is due 10:00 AM October 30, Wednesday, please start early.
• The problems should be solved individually. You should submit solutions for all problems to the online
judge (OJ) system, which will give a score for each submission automatically.
• You may discuss course material, programming languages, general techniques, and share test cases with
others.
• You’re encouraged to ask any question about problem description, environment setup, error informa tion, grammar, functions, methods etc., or post general ideas at Piazza. It can help others too!
• However, you may NOT read, possess, copy, or submit any part of other’s solution. You may not ask
others to directly debug your program or provide specific lines of solution. You should not access an other person’s account. Also, do not offer such help, and protect your account and code. Giving or
receiving inappropriate help is plagiarism, an infringement of academic integrity.
• You are not allowed to write your solution directly by or based on code generated by AI tools.
• Good luck and have fun!
2
1 UNFORTUNATE STOCKHOLDER
1 Unfortunate Stockholder
“I really hate green,” the poor man sighed, looking down, and found his beloved Alexandra Nikolaevna
Petrovskaya lying on the floor, stiff and cold. With her gone, his nearly hairless head now has one less hair.
A month ago, he was still a rich man, with positive daily profit from his investments. However, without
him noticing, some of his stocks had been falling for several days, and then suddenly hit the lower limit.
Quicker than he could take any actions, his other stocks also began falling.
Because he had so many stocks, he only checked the total profit every day.“Oh God! How I wish I had a
tool that can tell me the details of my stocks!”
1.1 Task
As it happens, you know how to use python, and you will kindly fulfill his wish by writing a python
program to give the details of his stocks. You will be given a list of numbers, representing the profit of his
stocks, and a series of queries. For each query, you should perform the corresponding operation and print the
result.
1.2 Input/Output Specification
1.2.1 Input
The first line contains a string of float numbers, representing the profit of the stocks.
The second line contains a single positive integer n, indicating the number of queries.
Each of the following n lines contains a query, with details shown in the Table below. All queries will be
given in one of the formats
• query, operation
• query, operation, start_index, end_index, step
query, operation, start_index, end_index, step means querying on the profit of a subset of the stocks ob tained by performing slicing operation. It is guaranteed that start_index, end_index and step are all integers.
If the subset of the stocks to be queried is empty, print Querying on empty list! (with a single space
at the end of the output) and do nothing else.
1.2.2 Output
n lines, each line the result of the query.
3
1.2 Input/Output Specification 1 UNFORTUNATE STOCKHOLDER
Query Operation Example Input Result
find
min find, min the min profit amongst all stocks
find, min, 1, 3, 1 the min profit amongst the sliced subset of stocks
max
find, max the max profit amongst all stocks
find, max, 5, 9, 2 the max profit amongst the sliced subset of stocks
index
a single index, 10 the profit of the stock with index i
positive integer i
slice index, slice, 2, 3, 1 the list of profits of the sliced subset of stocks
compute
avg
compute, avg the average profit of all stocks
compute, avg, 5, 12, 3 the average profit of the sliced subset of stocks
all compute, all the total profit of all stocks
compute, all, 6, 3, 2 the total profit of the sliced subset of stocks
reorder
asc
reorder, asc the reordered list of profits
of all stocks in ascending order
reorder, asc, 7, 30, 1 the list of profits with the profits of the
sliced stocks reordered in ascending order
desc
reorder, desc the reordered list of profits
of all stocks in descending order
reorder, desc, 3, 4, 2 the list of profits with the profits of the
sliced stocks reordered in descending order
rev
reorder, rev the reordered list of profits
of all stocks in reverse order
reorder, rev, 9, 3, 3 the list of profits with the profits of the
sliced stocks reordered in reverse order
1.2.3 Example
1. Input
1 4 5 3 4 2 5 −2 −3 0 2
5
find, min
find, max, 0, 3, 1
compute, avg, 2, 12, 1
reorder, rev
reorder, asc, 1, 6, 1
Output
−3.0
5.0
1.7777777777777777
[2.0, 0.0, −3.0, −2.0, 5.0, 2.0, 4.0, 3.0, 5.0, 4.0, 1.0]
[2.0, −3.0, −2.0, 0.0, 2.0, 5.0, 4.0, 3.0, 5.0, 4.0, 1.0]
4
1.3 Hint 2 AVERAGE RUNNING SPEED
2. Input
1 2 3 4 5 6
5
index, 5
index, slice, 1, 4, 2
compute, all
reorder, desc, 6, 3, −1
find, max, 2, 4, 1
Output
6.0
[2.0, 4.0]
21.0
[1.0, 2.0, 3.0, 4.0, 5.0, 6.0]
4.0
1.3 Hint
After each reorder query, the list is reordered (i.e., it is mutated), as shown in the examples.
2 Average Running Speed
As part of promoting a healthy lifestyle, the university has introduced a running App. The App generates
data points consecutively containing the student’s positions and timestamps during their running sessions.
The App helps generate useful statistics, such as distance covered and average speed. And students can freely
select specific data points for customized analysis.
2.1 Task
You are tasked with writing a program to process data points of a running session and then evaluate
a runner’s performance. Your program receives n data points at the beginning. The i-th data point Pi =
(xi
, yi
, ti), where xi and yi are the runner’s 2D coordinates, ti
is the timestamp measured in seconds. For
simplicity, we assume that runners travels along a straight path between two adjacent points, so the distance
between two adjacent data points is estimated using the Euclidean distance formula:
D(Pk, Pk−1) = √
(xk−xk−1)
2 + (yk−yk−1)
2
5
2.2 Input/Output Specification 2 AVERAGE RUNNING SPEED
Firstly, you need to estimate the average speed V of the entire session, note that the session starts at P0 and
ends at Pn−1:
V =
∑n
k=1 D(Pk, Pk−1)
tn−1 − t0
Then the runner will freely select m subsections, with the i-th subsection represented by the indices of two
data points, starti and endi
. And the runner wants to know what the average running speed is for each
subsection, i.e., the average speed V i running through Pstarti
, Pstarti+1, . . . , Pendi−1, Pendi
2.2 Input/Output Specification
2.2.1 Input
The first line contains a single integer n, the number of data points in the running session (2 ≤ n ≤ 100).
The next n lines of data points contains three integers each: xi
, yi
, ti
, where xi and yi
is the runner’s
coordinate (−100 ≤ xi
, yi ≤ 100), ti
is the timestamp at the i-th data point (0 ≤ t0 < t1 < t2 . . . < tn−1 ≤
103
).
The next line contains a single integer m, the number of the selected subsections.
The next m lines contains two values each: starti
, endi
, which represents the indices of start point and
end point of the i-th subsection (0 ≤ starti < endi < n).
2.2.2 Output
The first line is the average speed V of the entire session. And the next m lines: each line contains the
average speed V i for the i-th subsection. V and V i should be formatted to three decimal places.
2.2.3 Example
1. Input
4
1 2 1
** 5
4 8 12
2 1 18
1
1 3
Output
1.129
1.009
6
3 I OR E
2. Input
5
48 8 2
−83 −85 4
60 14 11
−37 −37 19
−15 −31 20
2
3 4
0 2
Output
25.943
22.804
37.176
3 I or E
Myers–Briggs Type Indicator (MBTI) is a assessment particularly popular in social occasions. There is
one dimension: energy orientation, which is divided into introversion and extraversion—— extraverted person
obtains energy from social interactions, while introverted person obtains energy from self-reflection.
However, a person’s energy orientation is not fixed. For example, a person who is initially classified as
introverted may turn out to be extraverted under some circumstances.
3.1 Task
In this scenario, a meeting consists of participants of three initial orientations: “E”, “I”, and “i”. You are
given a seating arrangement represented as an n × m matrix where n is the number of rows. And each seat
position indicates the energy orientation of a participant (E, I, or i). Your task is to print out the final energy
orientation in matrix format.
Participants will sit one by one, from the first row to the last row, and within each row, from left to right.
During this process, if an “i” participant is surrounded by introverted person (either “I” or “i”), they will change
their orientation to extraverted, denoted as “e”. A participant is considered surrounded by introverted person
if all their adjacent neighbors (up, down, left, right) are either I or i. If the participant is on the boundary
or corner, only the existing neighbors are considered.
There is a special case when the last participant seated: first update the previously seated participants
before considering the last one, in order to avoid potential conflicts.
7
3.2 Input/Output Specification 3 I OR E
3.2 Input/Output Specification
3.2.1 Input
The first line contains two integers n and m, representing the dimensions of the seating matrix (n × m),
(2 ≤ n, m ≤ 50). The following n lines each contain m separated characters c ∈ {E, I, i}, indicating the
energy orientation of the participants in each seat.
3.2.2 Output
You should output n lines, each containing one list, representing the final energy orientation of the par ticipants after they are seated in order.
3.2.3 Example
1. Input
3 4
E I i I
i I i i
i I I i
Output
['E', 'I', 'e', 'I']
['i', 'I', 'i', 'e']
['e', 'I', 'I', 'i']
Case Explanation: for convenience, we use a tuple (i, j) (count from 1), to represent the seat located
at the i-th row and j-th column. The orientation of the participant changed in the following order:
(a) (1, 3) changed when (2, 3) seated.
(b) (3, 1) changed when (3, 2) seated.
(c) (2, 3) changed when (3, 3) seated. Remember to update the previously seated participants before
the last one.
2. Input
5 5
E I i I E
i I i I I
I i I i E
I I i i I
i I I I i
8
4 TURTLE BLIND BOXES
Output
['E', 'I', 'e', 'I', 'E']
['i', 'I', 'i', 'I', 'I']
['I', 'e', 'I', 'i', 'E']
['I', 'I', 'e', 'i', 'I']
['e', 'I', 'I', 'I', 'e']
Case Explanation: The orientation of the participant changed in the following order:
(a) (1, 3) changed when (2, 3) seated.
(b) (3, 2) changed when (4, 2) seated.
(c) (5, 1) changed when (5, 2) seated.
(d) (4, 3) changed when (5, 3) seated.
(e) (5, 5) changed when (5, 5) seated.
4 Turtle Blind Boxes
Blind box opening games have become increasingly popular on platforms such as TikTok. In this assign ment, you will simulate a blind box opening game where the contents are small glass turtles of different colors
and patterns. The objective is to simulate the entire process of purchasing, opening, and placing these turtles
in a grid, following specific rules to either eliminate or reward the player with additional blind boxes based
on turtle combinations.
Each turtle has a color and a pattern, with the following possibilities:
• Colors: Red, Orange, Yellow, Green, Blue
• Patterns: Patterned, Unpatterned
The game uses a 3x3 grid to display the turtles, and there are several conditions that trigger rewards or elimi nations during the gameplay.
4.1 Task
You are required to write a Python program that simulates this turtle blind box game. The game follows
specific rules for rewarding the player with extra blind boxes or eliminating turtles from the grid. The detailed
task breakdown is as follows:
1. Get Blind Box Content: Each blind box contains one glass turtle with a randomly generated color and
pattern combination.
9
4.2 Input/Output Specification 4 TURTLE BLIND BOXES
2. Wish Mechanism: The player can wish for a specific color and pattern combination. If a turtle match ing the player’s wish is opened, they are immediately rewarded with one additional blind box.
3. Grid Filling: Each turtle is placed in a 3x3 grid (like a Tic-Tac-Toe board), and the turtles are placed
in the grid according to the numbered order of the cells (1 to 9), where 1 is the top-left and 9 is the
bottom-right.
4. Elimination and Reward Rules: After the grid is filled or all blind boxes have been opened, perform
the following operations in the specified order:
(a) All Different: If the grid is full and all turtles in the grid are different, remove all turtles and
reward the player with 5 additional blind boxes.
(b) Three of a Kind: If three identical turtles align horizontally, vertically, or diagonally, reward the
player with 5 additional blind boxes. The turtles remain in the grid. If there are multiple triples at
the same time, each triple should be given 5 new blind boxes.
(c) Pairs: If two identical turtles are found, they are eliminated from the grid, and the player is
rewarded with 1 additional blind box per pair. Turtles in cells with smaller numbers (lower numbered positions in the grid) are prioritized for removal.
5. End Condition: The game ends when no more blind boxes are available, and no turtles can be elimi nated.
4.2 Input/Output Specification
4.2.1 Input
The program will accept the following four lines of input:
1. The number of initial blind boxes purchased.
2. The player’s wish for a specific turtle’s color and pattern. Use two letters separated by a space to repre sent turtle.
3. A list of randomly generated turtles, with two lines:
• The first line represents the colors of the turtles, using the first letter of each color: R (Red), O
(Orange), Y (Yellow), G (Green), B (Blue).
• The second line represents the patterns of the turtles, using the first letter of each pattern: P
(Patterned), U (Unpatterned).
10
4.2 Input/Output Specification 4 TURTLE BLIND BOXES
The color and pattern of the i-th turtle are represented by the i-th letter in the third and fourth rows. The
number of turtles provided is undetermined, but it’s guaranteed to be larger than the number required for the
simulation.
4.2.2 Output
At the end of the game, output the list of eliminated turtles in the order they were removed from the grid.
Turtles should be represented by tuples of (color, pattern). At the end of the game, the remaining turtles in the
grid should also be eliminated in the order of the numbers in the nine-square grid. You can use print(list)
directly.
4.2.3 Example
1. Input
10
R U
YOBOOBRGOGYBYRYYGBO
UUUUPUUPPPUUUUPUUPU
Output
[('O', 'U'), ('O', 'U'), ('B', 'U'), ('B', 'U'), ('O', 'P'), ('O', 'P'),
('Y', 'U'), ('Y', 'U'), ('G', 'P'), ('G', 'P'), ('R', 'U'), ('R', 'U'),
('Y', 'U'), ('Y', 'U'), ('O', 'U'), ('G', 'U'), ('B', 'P'), ('B', 'U'),
('Y', 'P')]
2. Input
12
R P
RYOYYYROBYRBGGYOGBBYOBYBRYGOROROYGORGOY
PUPPPPUUPPPUUUPPPUPUPPUUPUPUPPUUUUPUUPU
Output
[('Y', 'P'), ('Y', 'P'), ('R', 'P'), ('R', 'P'), ('Y', 'P'), ('Y', 'P'),
('G', 'U'), ('G', 'U'), ('O', 'P'), ('O', 'P'), ('B', 'U'), ('B', 'U'),
('B', 'P'), ('B', 'P'), ('Y', 'U'), ('Y', 'U'), ('B', 'U'), ('R', 'P'),
('O', 'P'), ('B', 'P'), ('G', 'P'), ('Y', 'P'), ('R', 'U'), ('O', 'U'),
('Y', 'U'), ('Y', 'U'), ('Y', 'U'), ('O', 'U'), ('O', 'U'), ('O', 'P'),
('O', 'P'), ('R', 'U'), ('R', 'U'), ('G', 'U'), ('G', 'U'), ('Y', 'U'),
('G', 'P'), ('O', 'P'), ('R', 'P')]
11
4.3 Hint 4 TURTLE BLIND BOXES
4.3 Hint
• Randomly generate test data for debugging: To test your implementation, you can generate random
turtle combinations and simulate different scenarios (e.g., many identical turtles, all different turtles) to
check if the elimination rules are applied correctly.
• Pay attention to the execution order: Make sure that the elimination rules (e.g., three of a kind,
pairs, all different) are applied in the correct sequence. Follow the order of operations as specified in
the task to ensure accurate simulation.
• Modular design: During the implementation process, keep your code modular by breaking down dif ferent functionalities (e.g., adding turtles to the grid, checking for three of a kind, eliminating pairs) into
separate functions. This will make your code easier to understand, debug, and extend.
12

請加QQ:99515681  郵箱:99515681@qq.com   WX:codinghelp




 

掃一掃在手機打開當前頁
  • 上一篇:CSCI 201代做、代寫c/c++,Python編程
  • 下一篇:CE243編程代寫、代做C/C++程序語言
  • 無相關信息
    合肥生活資訊

    合肥圖文信息
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    出評 開團工具
    出評 開團工具
    挖掘機濾芯提升發動機性能
    挖掘機濾芯提升發動機性能
    海信羅馬假日洗衣機亮相AWE  復古美學與現代科技完美結合
    海信羅馬假日洗衣機亮相AWE 復古美學與現代
    合肥機場巴士4號線
    合肥機場巴士4號線
    合肥機場巴士3號線
    合肥機場巴士3號線
    合肥機場巴士2號線
    合肥機場巴士2號線
    合肥機場巴士1號線
    合肥機場巴士1號線
  • 短信驗證碼 酒店vi設計 deepseek 幣安下載 AI生圖 AI寫作 aippt AI生成PPT 阿里商辦

    關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
    ICP備06013414號-3 公安備 42010502001045

    日韩精品一区二区三区高清_久久国产热这里只有精品8_天天做爽夜夜做爽_一本岛在免费一二三区

      <em id="rw4ev"></em>

        <tr id="rw4ev"></tr>

        <nav id="rw4ev"></nav>
        <strike id="rw4ev"><pre id="rw4ev"></pre></strike>
        激情久久久久久久久久久久久久久久| 欧美mv日韩mv国产网站| 国产色爱av资源综合区| 亚洲在线观看| 亚洲欧洲日本mm| 欧美激情在线观看| 久久亚洲欧美| 欧美日韩亚洲高清一区二区| 一区二区av| 国产精品免费观看在线| 欧美日韩另类国产亚洲欧美一级| 国产精品腿扒开做爽爽爽挤奶网站| 欧美激情视频给我| 欧美精品免费在线观看| 国产精品萝li| 欧美在线免费观看亚洲| 欧美色视频日本高清在线观看| 欧美精品导航| 国产精品久久久久久av福利软件| 亚洲精品一区二区三区樱花| 国产精品美女在线观看| 欧美专区在线观看一区| 亚洲午夜一区二区| 欧美性猛交99久久久久99按摩| 久久成人免费| 国产精品久久久免费| 国产精品稀缺呦系列在线| 在线成人免费视频| 欧美色道久久88综合亚洲精品| 国产一区二区三区奇米久涩| 久久久久国产一区二区三区四区| 亚洲男同1069视频| av成人手机在线| 99热免费精品在线观看| 久久久.com| 久久久久久亚洲综合影院红桃| 国产一区二区三区久久久| 亚洲靠逼com| 蜜桃精品久久久久久久免费影院| 在线观看国产精品淫| 亚洲国产99精品国自产| 亚洲女爱视频在线| 日韩视频免费观看高清在线视频| 国产精品丝袜久久久久久app| 亚洲九九九在线观看| 亚洲丰满少妇videoshd| 亚洲精品久久久一区二区三区| 在线欧美福利| 国产自产在线视频一区| 亚洲一区美女视频在线观看免费| 亚洲国产日韩综合一区| 国产精品久久国产精麻豆99网站| 国产原创一区二区| 亚洲精品网址在线观看| 欧美日韩成人精品| 亚洲综合精品| 亚洲字幕在线观看| 国模一区二区三区| 免费在线观看日韩欧美| 欧美夜福利tv在线| 在线观看精品视频| 欧美三级韩国三级日本三斤| 久久久99精品免费观看不卡| 久久久久久自在自线| 国产精品永久免费视频| 一区二区精品在线观看| 欧美日韩人人澡狠狠躁视频| 久久久久久久尹人综合网亚洲| 久久综合伊人77777| 亚洲男人的天堂在线观看| 亚洲制服丝袜在线| 亚洲精品美女免费| 99这里只有久久精品视频| 欧美在线视频二区| 在线视频中文亚洲| 欧美视频福利| 欧美成人精品一区二区| 久久国产日韩| 久久久蜜臀国产一区二区| 欧美美女视频| 久久精品一区二区国产| 国产精品第一页第二页第三页| 激情久久一区| 久久国产精彩视频| 国产亚洲成精品久久| 欧美成在线视频| 午夜一区不卡| 另类春色校园亚洲| 亚洲二区三区四区| 欧美精品情趣视频| 亚洲人被黑人高潮完整版| 久久夜色精品一区| 欧美一区永久视频免费观看| 亚洲欧美日本日韩| 国产在线观看91精品一区| 亚洲第一二三四五区| 久久久国产亚洲精品| 午夜精品久久久久久久99樱桃| 午夜一区在线| 国产一区日韩二区欧美三区| 国外成人在线视频| 国产日韩欧美电影在线观看| 亚洲欧美日韩精品综合在线观看| 欧美啪啪一区| 亚洲一区免费网站| 久久视频国产精品免费视频在线| 亚洲欧美日韩国产中文| 欧美亚洲日本国产| 美乳少妇欧美精品| 久久亚洲精品伦理| 亚洲欧洲日韩在线| 一区二区三区四区蜜桃| 在线观看欧美一区| 国内精品模特av私拍在线观看| 久久深夜福利| 99精品久久免费看蜜臀剧情介绍| 99国产精品| 亚洲午夜精品一区二区| 亚洲美女在线观看| 免费成人美女女| 在线日韩一区二区| 国产精品成人午夜| 亚洲人成在线观看一区二区| 欧美专区在线观看| 欧美主播一区二区三区美女 久久精品人| 国产精品手机在线| 欲香欲色天天天综合和网| 亚洲福利视频网| 一区二区高清在线| 久久综合一区二区三区| 国产毛片一区| 欧美精品在线免费观看| 亚洲一区二区久久| 影音先锋中文字幕一区二区| 狠狠久久亚洲欧美| 国产精品尤物福利片在线观看| 亚洲香蕉伊综合在人在线视看| 久久精品欧美| 亚洲人永久免费| 国产精品亚洲美女av网站| 亚洲第一中文字幕在线观看| 欧美高清在线视频观看不卡| 国产精品久久久久久久久借妻| 欧美专区亚洲专区| 欧美日韩视频在线观看一区二区三区| 国产亚洲成人一区| 亚洲电影专区| 黄色一区三区| 亚洲综合欧美| 欧美日韩一区三区四区| 欧美韩国一区| 久久久久成人精品免费播放动漫| 久久国产精品一区二区三区四区| 欧美视频日韩视频在线观看| 亚洲美女av在线播放| 久久久久国产一区二区三区| 亚洲精品在线观看视频| 国产精品日韩电影| 99视频有精品| 在线视频精品一| 欧美福利一区二区| 国产综合久久久久影院| 亚洲欧美在线高清| 国产专区精品视频|