日韩精品一区二区三区高清_久久国产热这里只有精品8_天天做爽夜夜做爽_一本岛在免费一二三区

合肥生活安徽新聞合肥交通合肥房產生活服務合肥教育合肥招聘合肥旅游文化藝術合肥美食合肥地圖合肥社保合肥醫院企業服務合肥法律

代做MAT301H1、代寫R編程語言

時間:2024-01-20  來源:合肥網hfw.cc  作者:hfw.cc 我要糾錯



niversity of Toronto
Faculty of Arts and Sciences
MAT301H1 - S: Groups and Symmetries
Winter 2024
Homework 1
1 Problems to be submitted
Make sure you follow all the indications as stated in the syllabus.
Don*t let yourself be impressed by the length of the homework or how the problems look. They
are divided into parts to guide you through the problems and make the ideas accessible.
In this problem set we explore the notion of symmetries of some objects and in the techniques
of counting how many symmetries there are via linear algebra.
 In problem 1 we develop the cycle notation and the product of transposition. We prove the sign
is well defined.
 Problem 2 explores the dihedral group and it is solved in exactly the same way as we studied
the symmetries of the coloured cube in the class. Think of that example while solving.
Problem 3 develops the notion of order in groups and how to use the ideas we develop in problem
2 to study the orders in the dihedral group.
 Problem 4 explores the notion of groups being the same or different (which later we will denote
by the term isomorphic).
 Remember, our objective in this course is in great part how to use groups to compute. We
develop the notion of §what do we mean by computing with groups§ by exploring this examples,
which as we move forward will build up towards very beautiful ideas.
1. In lecture we have discussed the symmetric group (i.e. the group of permutations of n distinct elements).
We defined the cycle notation for its elements. We denoted this group by Sn.
(a) (3 points) Write in disjoint cycles all the elements of S4 (that is, the permutations of the 4 elements
1, 2, 3, 4.)
Hint: Don*t over think it. Just do it.
(b) (1 point) Let a1, ..., ak be different numbers from 1, 2, ..., n. Prove that
(a1, ..., ak) = (ak, ak?1)....(ak, a1)
For example, (1, 2, 3, 4) = (4, 3)(4, 2)(4, 1).
Note: The above parenthesis denote cycle notations of permutations.
(c) (1 point) Use the previous fact to prove the following: All permutations can be written as a com-
position of transpositions.
1
(d) (4 points) It is not true that a permutation can be written as a composition of transpositions in a
unique way. However, the following fact is true: The parity of the number of transpositions used
to write a fixed permutation is invariant.
Prove the above fact.
Hint: Taking a smaller than b, what is the parity of the number of times ways that a and b cross
each other as you read the transpositions in a given composition from the original order to the new
one?
(e) (1 point) Given a permutation 考 ﹋ Sn, we define its sign, and denote if by sgn(考), as 1 or ?1
according to whether we used an even number or an odd number of transpositions to write 考.
Explain why the sign is well defined and verify that
sgn(考1考2) = sgn(考1)sgn(考2),
where 考1, 考2 are any two permutations.
2. Let n be a positive integer. Consider the points
Pk = (cos(2羽k/n), sin(2羽k/n)),
for k = 0, 1, ..., n? 1. They are the n vertices of a regular n?gon. Notice that P0 = (1, 0).
We also call the midpoint between Pk and Pk+1 by Mk (the subindices run modulo n, so Mn?1 is the
midpoint between Pn?1 and P0.)
Notice that the vertices and the midpoints alternate. If we read them counterclockwise they are
P0,M0, P1,M1, ..., Pn?1,Mn?1.
They create 2n segments, each with one vertex and one midpoint as endpoints. We will call these
segments by chambers and denote chamber P0M0 by C.
We want to answer the question: what is the structure of the linear transformations 樸 : R2 ?↙ R2
that send the vertices to the vertices and preserve their adjacency. In other words, the isometries of the
n? gon.?
The isometries of the n?gon form a group which is called the Dihedral Group and denoted by Dn.
(a) (1 point) Verify that the isometries of the n?gon always send C to some chamber.
(b) (2 points) Let 樸1,樸2 : R2 ?↙ R2 be any two isometries of the n?gon. Prove that if 樸1 and 樸2
send the chamber C to the same place, then
樸1 = 樸2.
Notice that the above equality is an equality of linear transformations.
(c) (1 point) Let S : R2 ?↙ R2 be the reflection in the X-axis and R : R2 ?↙ R2 a counterclockwise
rotation by an angle of 2羽/n. Justify that S and T are isometries of the n? gon.
(d) (2 points) By tracking its action on C, justify the following fact: all isometries of the n?gon can
be written as compositions of S and R.
(e) (1 point) Use the above facts to justify the following fact: there are as exactly the same number of
chambers than of isometries of the n?gon.
(f) (1 point) How many isometries does the n-gon has?
(g) (2 points) Suppose we ignore the midpoints and we instead call the sides of the n?gon the chambers.
In this case, there are n chambers and so the number of isometries is not the same a the number of
chambers.
What part of the previous process, when we consider the midpoints, breaks down if we only consider
the sides as the chambers? Explain carefully.
Page 2
3. We say a transformation has order n if n is the smallest positive integer such that when you perform
the transformation n times you obtain the identity transformation.
For example, in the permutation group S4, the permutation (1, 2, 3) has order 3 because:
(1, 2, 3)(1, 2, 3) = (1, 3, 2)
and
(1, 2, 3)(1, 2, 3)(1, 2, 3) = (1, 3, 2)(1, 2, 3) = (1)(2)(3) = identity.
Another example: for the isometries of the coloured cube, each of the reflections has order 2.
(a) (3 points) Compute the order of all the elements of S4.
Hint: This is easy. Just do it by hand and notice there is a lot of repetition! Don*t over think it!
(b) (2 points) Prove that in Dn, the dihedral group defined in the previous problem, R has order n.
(c) (1 point) Let 樸 be an element of the Dihedral group Dn. Prove that it has a finite order, that is,
prove there exists a positive integer m such that
樸m = identity.
Hint: What happens with the chambers as you apply succesive powers of 樸? Problem 2(b) will be
useful here.
(d) (2 points) Let 樸 be an element of the Dihedral group Dn whose order is m. Denote by Ck = 樸k(C)
for k = 0, 1, ...,m ? 1. That is, C0, ..., Cm?1 is the set of chambers that you can reach with the
powers of 樸.
Let D be a chamber different from C0, ..., Cm?1, in case there exists one. There exists 朵, an isometry,
such that 朵(C) = D by problem 2. Denote by Dk = 樸k(D) for k = 0, 1, ...,m? 1.
Prove that D0, ...,Dm?1 are different among themselves and different from all of C0, ..., Cm?1.
(e) (2 points) Prove that the order of each element of the Dihedral group divides 2n.
Hint: Using the previous part you can divide the set of all chambers, which has cardinality 2n,
into subsets of order m. These subsets consist of the chambers reached from a given chamber using
樸0, ...,樸m?1.
4. We have constructed several groups so far. Amopng then are the following groups:
1. The permutation group S4,
2. The isometries of the coloured cube (what we did in lecture),
3. The Dihedral group D12, that is, the isometries of the 12?gon (called a regular dodecagon).
We have proven all of them have 24 elements! (Make sure you understand this) In this question we
explore whether they are the same or different group.
A cube has 8 vertices. If v is a vertex, then ?v is also a vertex (the vertex farthest away!). We can
group the vertices into four pairs of antipodal vertices like this.
(a) (2 points) Prove that every isometry of the coloured cube sends a pair antipodal vertices to another
(possibly different) set of antipodal vertices.
Hint: You do not need to check this for the 24 isometries. We have seen in lecture all the isometries
are built out of three specific ones! Use that to your advantage.
(b) (3 points) Call L1, L2, L3, L4 the four pairs of antipodal points we have defined. By the previous
part, there exists a permutation 考 of S4 such that
樸(Li) = L考(i).
(Make sure you understand how to construct it!) Call that permutation by P (樸).
Page 3
Justify that
P (樸1 ? 樸2) = P (樸1) ? P (樸2).
Remark: The ? on the right hand side is the composition of permutations in S4, while the ? in
the left hand side is the composition of linear transformations.
(c) (2 points) Prove that if 樸1,樸2 are two permutations of the coloured cube with P (樸1) = P (樸2)
then 樸1 = 樸2.
Hint: Use Linear Algebra!
(d) (1 point) We have explained in lecture that a group is a set with a multiplication table. Explain
why the above parts proves that the multiplication tables of S4 and of the symmetries of the cube
are the same.
You don*t have to be extremely precise, as we have not developed the exact terminology for this.
We are understanding the notions at the moment.
Remark: Once we define all appropriately, we shall say that the groups are isomorphic and the
map P is an isomorphism.
(e) (2 points) Prove that the Dihedral group D12 has an essentially different table to the other two
groups, despite having the same number of elements.
Hint: Who would correspond to R?
請加QQ:99515681 或郵箱:99515681@qq.com   WX:codehelp

掃一掃在手機打開當前頁
  • 上一篇:EI論文發表 發表EI論文 EI期刊發表
  • 下一篇:EI會議論文發表流程講解
  • 無相關信息
    合肥生活資訊

    合肥圖文信息
    2025年10月份更新拼多多改銷助手小象助手多多出評軟件
    2025年10月份更新拼多多改銷助手小象助手多
    有限元分析 CAE仿真分析服務-企業/產品研發/客戶要求/設計優化
    有限元分析 CAE仿真分析服務-企業/產品研發
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    急尋熱仿真分析?代做熱仿真服務+熱設計優化
    出評 開團工具
    出評 開團工具
    挖掘機濾芯提升發動機性能
    挖掘機濾芯提升發動機性能
    海信羅馬假日洗衣機亮相AWE  復古美學與現代科技完美結合
    海信羅馬假日洗衣機亮相AWE 復古美學與現代
    合肥機場巴士4號線
    合肥機場巴士4號線
    合肥機場巴士3號線
    合肥機場巴士3號線
  • 短信驗證碼 trae 豆包網頁版入口 目錄網 排行網

    關于我們 | 打賞支持 | 廣告服務 | 聯系我們 | 網站地圖 | 免責聲明 | 幫助中心 | 友情鏈接 |

    Copyright © 2025 hfw.cc Inc. All Rights Reserved. 合肥網 版權所有
    ICP備06013414號-3 公安備 42010502001045

    日韩精品一区二区三区高清_久久国产热这里只有精品8_天天做爽夜夜做爽_一本岛在免费一二三区

      <em id="rw4ev"></em>

        <tr id="rw4ev"></tr>

        <nav id="rw4ev"></nav>
        <strike id="rw4ev"><pre id="rw4ev"></pre></strike>
        国产欧美日韩一区二区三区在线| 国产精品视频一二三| 亚洲精品一区二区三区99| 久久久久国产精品厨房| 欧美日韩美女| 国产精品欧美久久久久无广告| 欧美福利视频在线观看| 久久精品在线免费观看| 久久久人成影片一区二区三区观看| 欧美午夜精品久久久久久浪潮| 国产区欧美区日韩区| 亚洲欧美综合一区| 欧美日韩国产丝袜另类| 一区二区三区在线观看视频| 亚洲一区二区三区在线看| 国产精品麻豆成人av电影艾秋| 精品成人乱色一区二区| 亚洲人成在线播放网站岛国| 伊人久久亚洲热| 亚洲欧洲精品一区二区精品久久久| 亚洲六月丁香色婷婷综合久久| 国内成+人亚洲+欧美+综合在线| 国产一区二区电影在线观看| 农夫在线精品视频免费观看| 亚洲欧美日韩视频一区| 久久永久免费| 亚洲欧洲日韩综合二区| 久久久久一区二区三区| 葵司免费一区二区三区四区五区| 久久精品国产综合精品| 日韩视频中午一区| 久久久www免费人成黑人精品| 国产精品美女久久久久av超清| 亚洲一区二区三区四区在线观看| 国产日韩欧美一区二区三区四区| 蜜桃av一区二区在线观看| 欧美电影免费| 午夜精品久久久久影视| 国产一区成人| 亚洲国产va精品久久久不卡综合| 亚洲精品一区二区三区福利| 久久亚洲欧洲| 99热免费精品在线观看| 欧美亚洲尤物久久| 久久精品综合一区| 久久精品理论片| 国产欧美丝祙| 久久久免费av| 国产午夜精品久久| 国产一区二区三区高清| 黄色国产精品| 在线成人www免费观看视频| 国产精品自拍一区| 日韩视频一区二区三区在线播放免费观看| 亚洲欧美一区二区三区在线| 免费亚洲视频| 樱桃视频在线观看一区| 亚洲免费中文| 国产精品sss| 国产精品一级二级三级| 欧美精品一区二区三区一线天视频| 国产一区二区三区最好精华液| 欧美v国产在线一区二区三区| 免费黄网站欧美| 亚洲毛片在线| 欧美精品亚洲一区二区在线播放| 国产午夜久久久久| 国产色产综合色产在线视频| 亚洲天天影视| 久久蜜臀精品av| 国产免费成人av| 久久精品免费观看| 欧美日韩在线免费观看| 久久久777| 亚洲日本欧美天堂| 国产日韩在线一区二区三区| 亚洲高清网站| 亚洲国产精品va在线看黑人| 亚洲伦理一区| 在线观看亚洲一区| 国产一区二区精品| 激情伊人五月天久久综合| 欧美三级特黄| 国产精品福利网| 欧美激情综合| 欧美一区2区三区4区公司二百| 老**午夜毛片一区二区三区| 国模大胆一区二区三区| 在线免费日韩片| 亚洲激情校园春色| 午夜精品一区二区三区在线视| 欧美日韩亚洲高清| 亚洲国内欧美| 欧美一区二区三区日韩视频| 亚洲一区二区三区免费观看| 欧美视频一区二区三区四区| 精品成人乱色一区二区| 99re热这里只有精品免费视频| 国产精品影音先锋| 国产主播精品| 蜜月aⅴ免费一区二区三区| 国产在线视频欧美一区二区三区| 欧美日韩国产高清| 亚洲精品小视频| 欧美日本簧片| 国产亚洲综合性久久久影院| 国内成+人亚洲+欧美+综合在线| 欧美一区二区成人6969| 日韩午夜免费视频| 欧美一二三区精品| 99视频精品| 亚洲一区二区三区视频播放| 欧美一区二区三区免费观看视频| 国模精品一区二区三区色天香| 欧美日韩激情小视频| 欧美在线3区| 亚洲一区二区在线观看视频| 一本色道久久精品| 国产视频在线观看一区二区三区| 在线观看欧美日本| 亚洲第一精品在线| 欧美日韩国产免费观看| 欧美天堂亚洲电影院在线观看| 国产精品麻豆成人av电影艾秋| 欧美日本不卡高清| 欧美日韩国产精品自在自线| 狠狠爱www人成狠狠爱综合网| 国产精品日韩一区二区三区| 亚洲欧美日韩国产综合精品二区| 欧美与黑人午夜性猛交久久久| 1204国产成人精品视频| 国产精品影音先锋| 欧美日韩一区二区在线观看视频| 欧美成在线观看| 在线免费观看日本欧美| 国产精品伊人日日| 亚洲天堂偷拍| 午夜天堂精品久久久久| 最近中文字幕日韩精品| 国产一级精品aaaaa看| 亚洲欧美视频一区二区三区| 一区二区三区四区精品| 黄色精品一区| 久久成人免费视频| 99热免费精品在线观看| 亚洲精品一区二区网址| 久久激五月天综合精品| 欧美日韩成人一区二区三区| 欧美精品观看| 亚洲欧洲日产国产网站| 亚洲精品亚洲人成人网| 亚洲欧美国产高清va在线播| 亚洲一区二区三区四区在线观看| 亚洲小说春色综合另类电影| 亚洲女同在线| 国产精品s色| 欧美精品一区二区三区高清aⅴ| 欧美午夜片在线免费观看| 国产精品视频你懂的| 国产一区二区三区四区老人| 国产综合色在线视频区| 欧美大片一区二区三区| 99亚洲视频| 久久亚洲精品网站|